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Online Service29/03/2022 · Using newton's second law F = Mass x Acceleration (a) 40 – W x cos60 = 5 x a 40 – 50 x cos60 = 5 x a 40 – 50() = 5 x a 40 – 25 = 5 x a 15 = 5 x a 15/5 = a 3m/s2 = a The next part of the question asked for the force exerted on the …
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Online Service2. an energy-absorbing mechanism or resistance circuit causing this decrease. 3. a reduction in the amplitude of an oscillation or vibration as a result of energy being dissipated as heat. "dampening" means: 1. To make damp. 2. To deaden, restrain, or depress. 3. To soundproof. Notice: Damping is energy dissipation and dampening is making
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Online Service· Substitute equation (2) in equation (3) X = A e (-c/2m) + √(c/2m)2 – k/m) t + B e (-c/2m) - √(c/2m)2 – k/m) t The behavior of the system depends upon whether the radial of equation (4) is real, imaginary or zero. When the damping term (c/2m)2 > (k/m) the exponents in the above 3 2 4 50.
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Online Service(h) displacement of a particle on the string at x= 2m and at time t= 5sec. [ Answer: (a) A= 1:25m (b) != 50Hz (c) f= 25=ˇHz (d) k= 1:3m 1 (e) = 2ˇ=1:3m (f) v= 50=1:3ms 1 = 1 (g) +ve xdirection (h) below the xaxis ] 2. Retry the previous problem for the wave: y= 0:25sin(0:3x+ 40t) [ Answer: (a) A= 0:25m (b) != 40Hz (c) f= 20
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